In late binding function call is resolved during runtime. Therefore compiler determines the type of object at runtime, and then binds the function call.
#include <iostream>
using namespace std;
class A
{
int x=5;
public:
void display()
{
std::cout << "Value of x is : " << x<<std::endl;
}
};
class B: public A
{
int y = 10;
public:
void display()
{
std::cout << "Value of y is : " <<y<< std::endl;
}
};
int main()
{
A *a;
B b;
a = &b;
a->display();
return 0;
}In the above example, * a is the base class pointer. The pointer can only access the base class members but not the members of the derived class. Although C++ permits the base pointer to point to any object derived from the base class, it cannot directly access the members of the derived class. Therefore, there is a need for virtual function which allows the base pointer to access the members of the derived class.
Let's see the simple example of C++ virtual function used to invoked the derived class in a program.
#include <iostream>
{
public:
virtual void display()
{
cout << "Base class is invoked"<<endl;
}
};
class B:public A
{
public:
void display()
{
cout << "Derived Class is invoked"<<endl;
}
};
int main()
{
A* a; //pointer of base class
B b; //object of derived class
a = &b;
a->display(); //Late Binding occurs
}Pure virtual function can be defined as:
virtual void display() = 0;
Let's see a simple example:
#include <iostream>
using namespace std;
class Base
{
public:
virtual void show() = 0;
};
class Derived : public Base
{
public:
void show()
{
std::cout << "Derived class is derived from the base class." << std::endl;
}
};
int main()
{
Base *bptr;
//Base b;
Derived d;
bptr = &d;
bptr->show();
return 0;
}In the above example, the base class contains the pure virtual function. Therefore, the base class is an abstract base class. We cannot create the object of the base class.
